{"id":76,"date":"2022-01-11T11:27:06","date_gmt":"2022-01-11T10:27:06","guid":{"rendered":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/?p=76"},"modified":"2022-01-17T17:26:26","modified_gmt":"2022-01-17T16:26:26","slug":"representation-des-donnees-types-et-valeurs-de-base","status":"publish","type":"post","link":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/2022\/01\/11\/representation-des-donnees-types-et-valeurs-de-base\/","title":{"rendered":"Repr\u00e9sentation des donn\u00e9es: types et valeurs de base"},"content":{"rendered":"\n

1- \u00c9criture d\u2019un entier positif dans une base b \u2a7e 2<\/span><\/h1>\n\n\n\n

On nous<\/span> demande de calculer la somme de 2 nombres binaires :  (00110011)2<\/sub>+ (00011100)2<\/sub> et (10110011)2<\/sub>+ (01011100 )2<\/sub> <\/span><\/h2>\n\n\n\n
b= 0b110011 + 0b11100\nprint(b)\n\nc= 0b10110011+ 0b1011100\nprint (c) <\/pre>\n\n\n\n
et voici les r\u00e9sultats obtenus : 79 et 271.<\/p>\n\n\n\n
2) Repr\u00e9sentation binaire d\u2019un entier relatif<\/span><\/h1>\n\n\n\n
Conversion de 45 en binaire avec compl\u00e9ment de 1 et 2 :<\/span><\/h2>\n\n\n\n
\n
\n
En binaire :  45=    0010 1101         <\/span>           <\/h2>\n<\/div>\n\n\n\n
\n
En compl\u00e9ment de 1 (inversion) : 1101 0010<\/span><\/h2>\n<\/div>\n\n\n\n
\n
En compl\u00e9ment de 2 (+1) : 1101 0011<\/span><\/h2>\n<\/div>\n<\/div>\n\n\n\n
Si on additionne la valeur obtenue en binaire et celle du compl\u00e9ment du compl\u00e9ment \u00e0 2 on obtient 0000 0000. Donc le compl\u00e9ment \u00e0 1 correspond \u00e0 l’inverse du nombre choisi, autrement dit on a fait 45-45 ce qui nous donne 0.<\/span><\/h2>\n\n\n\n
3) Repr\u00e9sentation approximative des nombres r\u00e9els<\/span><\/h1>\n\n\n\n
a=0.1\ns=0\nfor x in range(0,101):\n  s=a+s\n  print(s)<\/pre>\n\n\n\n
Voici une explosion de nombre (r\u00e9sultat) : <\/p>\n\n\n\n
0.1
0.2
0.30000000000000004
0.4
0.5
0.6
0.7
0.7999999999999999
0.8999999999999999
0.9999999999999999
1.0999999999999999
1.2
1.3
1.4000000000000001
1.5000000000000002
1.6000000000000003
1.7000000000000004
1.8000000000000005
1.9000000000000006
2.0000000000000004
2.1000000000000005
2.2000000000000006
2.3000000000000007
2.400000000000001
2.500000000000001
2.600000000000001
2.700000000000001
2.800000000000001
2.9000000000000012
3.0000000000000013
3.1000000000000014
3.2000000000000015
3.3000000000000016
3.4000000000000017
3.5000000000000018
3.600000000000002
3.700000000000002
3.800000000000002
3.900000000000002
4.000000000000002
4.100000000000001
4.200000000000001
4.300000000000001
4.4
4.5
4.6
4.699999999999999
4.799999999999999
4.899999999999999
4.999999999999998
5.099999999999998
5.1999999999999975
5.299999999999997
5.399999999999997
5.4999999999999964
5.599999999999996
5.699999999999996
5.799999999999995
5.899999999999995
5.999999999999995
6.099999999999994
6.199999999999994
6.299999999999994
6.399999999999993
6.499999999999993
6.5999999999999925
6.699999999999992
6.799999999999992
6.8999999999999915
6.999999999999991
7.099999999999991
7.19999999999999
7.29999999999999
7.39999999999999
7.499999999999989
7.599999999999989
7.699999999999989
7.799999999999988
7.899999999999988
7.999999999999988
8.099999999999987
8.199999999999987
8.299999999999986
8.399999999999986
8.499999999999986
8.599999999999985
8.699999999999985
8.799999999999985
8.899999999999984
8.999999999999984
9.099999999999984
9.199999999999983
9.299999999999983
9.399999999999983
9.499999999999982
9.599999999999982
9.699999999999982
9.799999999999981
9.89999999999998
9.99999999999998
10.09999999999998<\/p>\n\n\n\n
Les r\u00e9sultats ne sont pas pr\u00e9cis.<\/p>\n","protected":false},"excerpt":{"rendered":"
1- \u00c9criture d\u2019un entier positif dans une base b \u2a7e 2 On nous demande de calculer la somme de 2 nombres binaires :  (00110011)2+ (00011100)2 et (10110011)2+ (01011100 )2 et voici les r\u00e9sultats obtenus : 79 et 271. 2) Repr\u00e9sentation binaire d\u2019un entier relatif Conversion de 45 en binaire avec compl\u00e9ment de 1 et 2 […]<\/p>\n","protected":false},"author":11,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[1],"tags":[],"_links":{"self":[{"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/posts\/76"}],"collection":[{"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/users\/11"}],"replies":[{"embeddable":true,"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/comments?post=76"}],"version-history":[{"count":4,"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/posts\/76\/revisions"}],"predecessor-version":[{"id":85,"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/posts\/76\/revisions\/85"}],"wp:attachment":[{"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/media?parent=76"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/categories?post=76"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/yb-isn.fr\/2021\/nsi\/romain\/wp-json\/wp\/v2\/tags?post=76"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}