{"id":698,"date":"2026-03-10T08:21:26","date_gmt":"2026-03-10T07:21:26","guid":{"rendered":"https:\/\/yb-isn.fr\/2025\/spc\/?p=698"},"modified":"2026-04-24T08:12:39","modified_gmt":"2026-04-24T06:12:39","slug":"61-synthese-de-lacetate-disoamyle","status":"publish","type":"post","link":"https:\/\/yb-isn.fr\/2025\/spc\/?p=698","title":{"rendered":"61-synth\u00e8se de l&rsquo;ac\u00e9tate d&rsquo;isoamyle"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Lire livre Hatier pages 610 \u00e0 614<\/p>\n\n\n\n<p class=\"has-black-color has-pale-ocean-gradient-background has-text-color has-background has-link-color wp-elements-14a3f546de6540347f26de0d85bde463 wp-block-paragraph\">1) Regarder la vid\u00e9o : 4 minutes<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Esterification : synth\u00e8se de l&#039;ac\u00e9tate d&#039;isoamyle \u00e0 odeur de banane\" width=\"640\" height=\"360\" src=\"https:\/\/www.youtube.com\/embed\/DyE_nRDmrL0?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" referrerpolicy=\"strict-origin-when-cross-origin\" allowfullscreen><\/iframe>\n<\/div><\/figure>\n\n\n\n<p class=\"has-black-color has-pale-ocean-gradient-background has-text-color has-background has-link-color wp-elements-cbf33fd7aef51b6cdcdc714f12da6f77 wp-block-paragraph\">2) Exercice<\/p>\n\n\n\n<div class=\"wp-block-esab-accordion esab-i2gir8wx\" data-mode=\"global\" data-close=\"true\"><div class=\"esab__container\">\n<div class=\"wp-block-esab-accordion-child\"><div class=\"esab__head\" role=\"button\" aria-expanded=\"false\"><div class=\"esab__heading_txt\"><h6 class=\"esab__heading_tag\">Exercice :Synth\u00e8se d\u2019un ar\u00f4me de banane ,l\u2019ac\u00e9tate d\u2019isoamyle<\/h6><\/div><div class=\"esab__icon\"><div class=\"esab__collapse\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m3.5 20.5c-4.7-4.7-4.7-12.3 0-17 4.7-4.7 12.3-4.7 17 0 4.6 4.7 4.6 12.3 0 17-4.7 4.6-12.3 4.6-17 0zm0.9-0.9c4.2 4.2 11 4.2 15.2 0 4.2-4.2 4.2-11 0-15.2-4.2-4.3-11-4.3-15.2 0-4.3 4.2-4.3 11 0 15.2z\"><\/path><path d=\"m11.4 15.9v-3.3h-3.3c-0.3 0-0.6-0.3-0.6-0.6 0-0.4 0.3-0.6 0.6-0.6h3.3v-3.3c0-0.3 0.3-0.6 0.6-0.6 0.3 0 0.6 0.3 0.6 0.6v3.3h3.3c0.3 0 0.6 0.2 0.6 0.6q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2h-3.3v3.3q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2c-0.4 0-0.6-0.3-0.6-0.6z\"><\/path><\/svg> <\/div><div class=\"esab__expand\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m12 24c-6.6 0-12-5.4-12-12 0-6.6 5.4-12 12-12 6.6 0 12 5.4 12 12 0 6.6-5.4 12-12 12zm10.6-12c0-5.9-4.7-10.6-10.6-10.6-5.9 0-10.6 4.7-10.6 10.6 0 5.9 4.7 10.6 10.6 10.6 5.9 0 10.6-4.7 10.6-10.6z\"><\/path><path d=\"m5.6 11.3h12.8v1.4h-12.8z\"><\/path><\/svg> <\/div><\/div><\/div><div class=\"esab__body\">\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<h2>Synth\u00e8se d\u2019un ar\u00f4me de banane : l\u2019ac\u00e9tate d\u2019isoamyle<\/h2>\n\n<p>On r\u00e9alise la synth\u00e8se de l\u2019ac\u00e9tate d\u2019isoamyle, ester responsable d\u2019une odeur de banane, par r\u00e9action entre l\u2019acide \u00e9thano\u00efque et l\u2019alcool isoamylique (3-m\u00e9thylbutan-1-ol).<\/p>\n\n<p><strong>Donn\u00e9es<\/strong><\/p>\n<ul>\n  <li><em>M<\/em>(acide \u00e9thano\u00efque) = 60,0 g\u00b7mol<sup>\u22121<\/sup><\/li>\n  <li><em>M<\/em>(alcool isoamylique) = 88,0 g\u00b7mol<sup>\u22121<\/sup><\/li>\n  <li><em>M<\/em>(ac\u00e9tate d\u2019isoamyle) = 130,0 g\u00b7mol<sup>\u22121<\/sup><\/li>\n  <li><em>\u03c1<\/em>(acide \u00e9thano\u00efque) = 1,05 g\u00b7mL<sup>\u22121<\/sup><\/li>\n  <li><em>\u03c1<\/em>(alcool isoamylique) = 0,81 g\u00b7mL<sup>\u22121<\/sup><\/li>\n<\/ul>\n\n<p><strong>\u00c9quation de la r\u00e9action<\/strong><\/p>\n<p>acide \u00e9thano\u00efque + alcool isoamylique \u21cc ac\u00e9tate d\u2019isoamyle + eau<\/p>\n\n<p><strong>Protocole<\/strong><\/p>\n<p>On introduit dans un ballon :<\/p>\n<ul>\n  <li>V<sub>1<\/sub> = 20,0 mL d\u2019acide \u00e9thano\u00efque ;<\/li>\n  <li>V<sub>2<\/sub> = 22,0 mL d\u2019alcool isoamylique ;<\/li>\n  <li>quelques gouttes d\u2019acide sulfurique concentr\u00e9 ;<\/li>\n  <li>quelques grains de pierre ponce.<\/li>\n<\/ul>\n\n<p>On chauffe \u00e0 reflux pendant 20 min.<\/p>\n\n<p>Apr\u00e8s refroidissement, le m\u00e9lange est vers\u00e9 dans une ampoule \u00e0 d\u00e9canter, puis on ajoute de l\u2019eau sal\u00e9e. On \u00e9limine la phase aqueuse, on s\u00e8che la phase organique, puis on obtient une masse de produit \u00e9gale \u00e0 <strong>m = 21,1 g<\/strong>.<\/p>\n\n<p>On r\u00e9alise enfin une CCM avec trois d\u00e9p\u00f4ts :<\/p>\n<ul>\n  <li>A : alcool isoamylique ;<\/li>\n  <li>B : produit synth\u00e9tis\u00e9 ;<\/li>\n  <li>C : ac\u00e9tate d\u2019isoamyle pur.<\/li>\n<\/ul>\n\n<p>Le d\u00e9p\u00f4t B donne une tache principale \u00e0 la m\u00eame hauteur que C, et une petite tache \u00e0 la m\u00eame hauteur que A.<\/p>\n\n<p><strong>Questions<\/strong><\/p>\n<ol>\n  <li>Quel est le r\u00f4le du chauffage \u00e0 reflux ?<\/li>\n  <li>Quel est le r\u00f4le de l\u2019acide sulfurique ?<\/li>\n  <li>Calculer les quantit\u00e9s de mati\u00e8re initiales des deux r\u00e9actifs.<\/li>\n  <li>D\u00e9terminer le r\u00e9actif limitant.<\/li>\n  <li>Calculer la masse th\u00e9orique maximale d\u2019ac\u00e9tate d\u2019isoamyle.<\/li>\n  <li>Calculer le rendement de la synth\u00e8se.<\/li>\n  <li>Pourquoi ajoute-t-on de l\u2019eau sal\u00e9e dans l\u2019ampoule \u00e0 d\u00e9canter ?<\/li>\n  <li>Quelle phase conserve-t-on si l\u2019ester est peu soluble dans l\u2019eau et moins dense que l\u2019eau ?<\/li>\n  <li>Interpr\u00e9ter la CCM. Le produit est-il pur ?<\/li>\n  <li>Citer une m\u00e9thode simple permettant d\u2019am\u00e9liorer la puret\u00e9 du produit obtenu.<\/li>\n<\/ol>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<div class=\"wp-block-esab-accordion esab-e8148t3c\" data-mode=\"global\" data-close=\"true\"><div class=\"esab__container\">\n<div class=\"wp-block-esab-accordion-child\"><div class=\"esab__head\" role=\"button\" aria-expanded=\"false\"><div class=\"esab__heading_txt\"><h6 class=\"esab__heading_tag\">Corrig\u00e9 de l&rsquo;exercice<\/h6><\/div><div class=\"esab__icon\"><div class=\"esab__collapse\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m3.5 20.5c-4.7-4.7-4.7-12.3 0-17 4.7-4.7 12.3-4.7 17 0 4.6 4.7 4.6 12.3 0 17-4.7 4.6-12.3 4.6-17 0zm0.9-0.9c4.2 4.2 11 4.2 15.2 0 4.2-4.2 4.2-11 0-15.2-4.2-4.3-11-4.3-15.2 0-4.3 4.2-4.3 11 0 15.2z\"><\/path><path d=\"m11.4 15.9v-3.3h-3.3c-0.3 0-0.6-0.3-0.6-0.6 0-0.4 0.3-0.6 0.6-0.6h3.3v-3.3c0-0.3 0.3-0.6 0.6-0.6 0.3 0 0.6 0.3 0.6 0.6v3.3h3.3c0.3 0 0.6 0.2 0.6 0.6q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2h-3.3v3.3q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2c-0.4 0-0.6-0.3-0.6-0.6z\"><\/path><\/svg> <\/div><div class=\"esab__expand\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m12 24c-6.6 0-12-5.4-12-12 0-6.6 5.4-12 12-12 6.6 0 12 5.4 12 12 0 6.6-5.4 12-12 12zm10.6-12c0-5.9-4.7-10.6-10.6-10.6-5.9 0-10.6 4.7-10.6 10.6 0 5.9 4.7 10.6 10.6 10.6 5.9 0 10.6-4.7 10.6-10.6z\"><\/path><path d=\"m5.6 11.3h12.8v1.4h-12.8z\"><\/path><\/svg> <\/div><\/div><\/div><div class=\"esab__body\">\n<p class=\"wp-block-paragraph\">Corrig\u00e9 de l\u2019exercice<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. Chauffage \u00e0 reflux<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Il permet d\u2019augmenter la vitesse de r\u00e9action en chauffant, tout en \u00e9vitant les pertes de mati\u00e8re gr\u00e2ce \u00e0 la condensation des vapeurs.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. R\u00f4le de l\u2019acide sulfurique<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Il joue le r\u00f4le de <strong>catalyseur<\/strong> : il acc\u00e9l\u00e8re la r\u00e9action sans \u00eatre consomm\u00e9 au bilan. Il peut aussi favoriser l\u2019est\u00e9rification par son caract\u00e8re d\u00e9shydratant.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. Quantit\u00e9s de mati\u00e8re initiales<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Acide \u00e9thano\u00efque<\/strong><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>m<\/mi><mn>1<\/mn><\/msub><mo>=<\/mo><mi>\u03c1<\/mi><mi>V<\/mi><mo>=<\/mo><mn>1<\/mn><mo separator=\"true\">,<\/mo><mn>05<\/mn><mo>\u00d7<\/mo><mn>20<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><mo>=<\/mo><mn>21<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><mtext>&nbsp;g<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">m_1 = \\rho V = 1,05 \\times 20,0 = 21,0\\ \\text{g}<\/annotation><\/semantics><\/math>m1\u200b=\u03c1V=1,05\u00d720,0=21,0&nbsp;g <math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>n<\/mi><mn>1<\/mn><\/msub><mo>=<\/mo><mfrac><mrow><mn>21<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><\/mrow><mrow><mn>60<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><\/mrow><\/mfrac><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>350<\/mn><mtext>&nbsp;mol<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">n_1 = \\frac{21,0}{60,0} = 0,350\\ \\text{mol}<\/annotation><\/semantics><\/math>n1\u200b=60,021,0\u200b=0,350&nbsp;mol<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Alcool isoamylique<\/strong><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>m<\/mi><mn>2<\/mn><\/msub><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>81<\/mn><mo>\u00d7<\/mo><mn>22<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><mo>=<\/mo><mn>17<\/mn><mo separator=\"true\">,<\/mo><mn>82<\/mn><mtext>&nbsp;g<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">m_2 = 0,81 \\times 22,0 = 17,82\\ \\text{g}<\/annotation><\/semantics><\/math>m2\u200b=0,81\u00d722,0=17,82&nbsp;g <math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>n<\/mi><mn>2<\/mn><\/msub><mo>=<\/mo><mfrac><mrow><mn>17<\/mn><mo separator=\"true\">,<\/mo><mn>82<\/mn><\/mrow><mrow><mn>88<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><\/mrow><\/mfrac><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>202<\/mn><mtext>&nbsp;mol<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">n_2 = \\frac{17,82}{88,0} = 0,202\\ \\text{mol}<\/annotation><\/semantics><\/math>n2\u200b=88,017,82\u200b=0,202&nbsp;mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">4. R\u00e9actif limitant<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">La r\u00e9action est de proportion st\u0153chiom\u00e9trique 1:1.<br>Comme <math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>202<\/mn><mo>&lt;<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>350<\/mn><\/mrow><annotation encoding=\"application\/x-tex\">0,202 &lt; 0,350<\/annotation><\/semantics><\/math>0,202&lt;0,350, <strong>l\u2019alcool isoamylique est le r\u00e9actif limitant<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">5. Masse th\u00e9orique maximale d\u2019ester<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>n<\/mi><mi>max<\/mi><mo>\u2061<\/mo><\/msub><mo stretchy=\"false\">(<\/mo><mtext>ester<\/mtext><mo stretchy=\"false\">)<\/mo><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>202<\/mn><mtext>&nbsp;mol<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">n_{\\max}(\\text{ester}) = 0,202\\ \\text{mol}<\/annotation><\/semantics><\/math>nmax\u200b(ester)=0,202&nbsp;mol <math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><msub><mi>m<\/mi><mi>max<\/mi><mo>\u2061<\/mo><\/msub><mo>=<\/mo><mi>n<\/mi><mi>M<\/mi><mo>=<\/mo><mn>0<\/mn><mo separator=\"true\">,<\/mo><mn>202<\/mn><mo>\u00d7<\/mo><mn>130<\/mn><mo separator=\"true\">,<\/mo><mn>0<\/mn><mo>=<\/mo><mn>26<\/mn><mo separator=\"true\">,<\/mo><mn>3<\/mn><mtext>&nbsp;g<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">m_{\\max} = nM = 0,202 \\times 130,0 = 26,3\\ \\text{g}<\/annotation><\/semantics><\/math>mmax\u200b=nM=0,202\u00d7130,0=26,3&nbsp;g<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">6. Rendement<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\" display=\"block\"><semantics><mrow><mi>\u03b7<\/mi><mo>=<\/mo><mfrac><msub><mi>m<\/mi><mtext>exp<\/mtext><\/msub><msub><mi>m<\/mi><mtext>th<\/mtext><\/msub><\/mfrac><mo>\u00d7<\/mo><mn>100<\/mn><mo>=<\/mo><mfrac><mrow><mn>21<\/mn><mo separator=\"true\">,<\/mo><mn>1<\/mn><\/mrow><mrow><mn>26<\/mn><mo separator=\"true\">,<\/mo><mn>3<\/mn><\/mrow><\/mfrac><mo>\u00d7<\/mo><mn>100<\/mn><mo>\u2243<\/mo><mn>80<\/mn><mo separator=\"true\">,<\/mo><mn>2<\/mn><mi mathvariant=\"normal\">%<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">\\eta = \\frac{m_{\\text{exp}}}{m_{\\text{th}}}\\times 100 = \\frac{21,1}{26,3}\\times 100 \\simeq 80,2\\%<\/annotation><\/semantics><\/math>\u03b7=mth\u200bmexp\u200b\u200b\u00d7100=26,321,1\u200b\u00d7100\u224380,2%<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Rendement : 80 %<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">7. Pourquoi ajouter de l\u2019eau sal\u00e9e ?<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Elle favorise la s\u00e9paration des phases et diminue la solubilit\u00e9 de l\u2019ester dans la phase aqueuse.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">8. Phase \u00e0 conserver<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Si l\u2019ester est <strong>moins dense que l\u2019eau<\/strong>, il se trouve dans la <strong>phase sup\u00e9rieure<\/strong>.<br>C\u2019est donc <strong>la phase organique du haut<\/strong> qu\u2019il faut conserver.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">9. Interpr\u00e9tation de la CCM<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>La tache principale de B au m\u00eame niveau que C montre que le produit synth\u00e9tis\u00e9 contient bien <strong>l\u2019ac\u00e9tate d\u2019isoamyle<\/strong>.<\/li>\n\n\n\n<li>La petite tache de B au m\u00eame niveau que A montre qu\u2019il reste un peu <strong>d\u2019alcool isoamylique<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Le produit <strong>n\u2019est donc pas pur<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">10. Am\u00e9liorer la puret\u00e9<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">On peut faire une <strong>distillation<\/strong>, ou une <strong>nouvelle extraction\/lavage<\/strong>, selon le protocole vis\u00e9.<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n<p class=\"has-black-color has-pale-ocean-gradient-background has-text-color has-background has-link-color wp-elements-ee331487462749126580ba762dde92e9 wp-block-paragraph\">3) questionnaire: 12 questions<\/p>\n\n\n\n<div class=\"wp-block-esab-accordion esab-hae97mf8\" data-mode=\"global\" data-close=\"true\"><div class=\"esab__container\">\n<div class=\"wp-block-esab-accordion-child\"><div class=\"esab__head\" role=\"button\" aria-expanded=\"false\"><div class=\"esab__heading_txt\"><h6 class=\"esab__heading_tag\">QCM<\/h6><\/div><div class=\"esab__icon\"><div class=\"esab__collapse\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m3.5 20.5c-4.7-4.7-4.7-12.3 0-17 4.7-4.7 12.3-4.7 17 0 4.6 4.7 4.6 12.3 0 17-4.7 4.6-12.3 4.6-17 0zm0.9-0.9c4.2 4.2 11 4.2 15.2 0 4.2-4.2 4.2-11 0-15.2-4.2-4.3-11-4.3-15.2 0-4.3 4.2-4.3 11 0 15.2z\"><\/path><path d=\"m11.4 15.9v-3.3h-3.3c-0.3 0-0.6-0.3-0.6-0.6 0-0.4 0.3-0.6 0.6-0.6h3.3v-3.3c0-0.3 0.3-0.6 0.6-0.6 0.3 0 0.6 0.3 0.6 0.6v3.3h3.3c0.3 0 0.6 0.2 0.6 0.6q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2h-3.3v3.3q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2c-0.4 0-0.6-0.3-0.6-0.6z\"><\/path><\/svg> <\/div><div class=\"esab__expand\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m12 24c-6.6 0-12-5.4-12-12 0-6.6 5.4-12 12-12 6.6 0 12 5.4 12 12 0 6.6-5.4 12-12 12zm10.6-12c0-5.9-4.7-10.6-10.6-10.6-5.9 0-10.6 4.7-10.6 10.6 0 5.9 4.7 10.6 10.6 10.6 5.9 0 10.6-4.7 10.6-10.6z\"><\/path><path d=\"m5.6 11.3h12.8v1.4h-12.8z\"><\/path><\/svg> <\/div><\/div><\/div><div class=\"esab__body\">\n<p class=\"wp-block-paragraph\"><strong>1.<\/strong> Une est\u00e9rification met en jeu en g\u00e9n\u00e9ral :<br>A. un alcool et un acide carboxylique<br>B. un alcool et une base<br>C. un alcane et de l\u2019eau<br>D. un ester et un m\u00e9tal<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2.<\/strong> Le chauffage \u00e0 reflux sert principalement \u00e0 :<br>A. refroidir le m\u00e9lange<br>B. chauffer sans perte de mati\u00e8re<br>C. s\u00e9parer les produits<br>D. mesurer le pH<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3.<\/strong> Dans ce protocole, l\u2019acide sulfurique est :<br>A. le r\u00e9actif limitant<br>B. le solvant<br>C. un catalyseur<br>D. le produit principal<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>4.<\/strong> La quantit\u00e9 initiale d\u2019acide \u00e9thano\u00efque vaut :<br>A. 0,105 mol<br>B. 0,210 mol<br>C. 0,350 mol<br>D. 0,500 mol<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>5.<\/strong> La quantit\u00e9 initiale d\u2019alcool isoamylique vaut environ :<br>A. 0,202 mol<br>B. 0,350 mol<br>C. 0,810 mol<br>D. 1,82 mol<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>6.<\/strong> Le r\u00e9actif limitant est :<br>A. l\u2019acide \u00e9thano\u00efque<br>B. l\u2019alcool isoamylique<br>C. l\u2019eau<br>D. l\u2019acide sulfurique<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>7.<\/strong> La masse th\u00e9orique maximale d\u2019ester form\u00e9 est :<br>A. 13,0 g<br>B. 21,1 g<br>C. 26,3 g<br>D. 35,0 g<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>8.<\/strong> Le rendement de la synth\u00e8se est proche de :<br>A. 50 %<br>B. 68 %<br>C. 80 %<br>D. 95 %<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>9.<\/strong> Dans l\u2019ampoule \u00e0 d\u00e9canter, si l\u2019ester est moins dense que l\u2019eau, il se trouve :<br>A. dans la phase inf\u00e9rieure<br>B. dans la phase sup\u00e9rieure<br>C. dans le solide form\u00e9<br>D. dans les vapeurs<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>10.<\/strong> L\u2019ajout d\u2019eau sal\u00e9e permet surtout :<br>A. d\u2019acc\u00e9l\u00e9rer la r\u00e9action<br>B. de colorer le milieu<br>C. de mieux s\u00e9parer les phases<br>D. de neutraliser totalement l\u2019ester<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>11.<\/strong> En CCM, deux taches \u00e0 la m\u00eame hauteur signifient que les esp\u00e8ces :<br>A. ont la m\u00eame masse molaire<br>B. sont n\u00e9cessairement pures<br>C. ont le m\u00eame comportement dans l\u2019\u00e9luant<br>D. ont la m\u00eame densit\u00e9<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>12.<\/strong> Si le d\u00e9p\u00f4t B pr\u00e9sente une tache comme C et une tache comme A, alors :<br>A. le produit B est pur<br>B. B ne contient que l\u2019alcool<br>C. B contient l\u2019ester et encore un peu d\u2019alcool<br>D. la CCM est inexploitable<\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<div class=\"wp-block-esab-accordion esab-j15jjemm\" data-mode=\"global\"><div class=\"esab__container\">\n<div class=\"wp-block-esab-accordion-child\"><div class=\"esab__head\" role=\"button\" aria-expanded=\"false\"><div class=\"esab__heading_txt\"><p class=\"esab__heading_tag\">Corrig\u00e9 du qcm<\/p><\/div><div class=\"esab__icon\"><div class=\"esab__collapse\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m3.5 20.5c-4.7-4.7-4.7-12.3 0-17 4.7-4.7 12.3-4.7 17 0 4.6 4.7 4.6 12.3 0 17-4.7 4.6-12.3 4.6-17 0zm0.9-0.9c4.2 4.2 11 4.2 15.2 0 4.2-4.2 4.2-11 0-15.2-4.2-4.3-11-4.3-15.2 0-4.3 4.2-4.3 11 0 15.2z\"><\/path><path d=\"m11.4 15.9v-3.3h-3.3c-0.3 0-0.6-0.3-0.6-0.6 0-0.4 0.3-0.6 0.6-0.6h3.3v-3.3c0-0.3 0.3-0.6 0.6-0.6 0.3 0 0.6 0.3 0.6 0.6v3.3h3.3c0.3 0 0.6 0.2 0.6 0.6q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2h-3.3v3.3q0 0.2-0.2 0.4-0.2 0.2-0.4 0.2c-0.4 0-0.6-0.3-0.6-0.6z\"><\/path><\/svg> <\/div><div class=\"esab__expand\"> <svg version=\"1.2\" viewBox=\"0 0 24 24\" width=\"24\" height=\"24\"><path fill-rule=\"evenodd\" d=\"m12 24c-6.6 0-12-5.4-12-12 0-6.6 5.4-12 12-12 6.6 0 12 5.4 12 12 0 6.6-5.4 12-12 12zm10.6-12c0-5.9-4.7-10.6-10.6-10.6-5.9 0-10.6 4.7-10.6 10.6 0 5.9 4.7 10.6 10.6 10.6 5.9 0 10.6-4.7 10.6-10.6z\"><\/path><path d=\"m5.6 11.3h12.8v1.4h-12.8z\"><\/path><\/svg> <\/div><\/div><\/div><div class=\"esab__body\">\n<p class=\"wp-block-paragraph\">Corrig\u00e9 du QCM<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<figure class=\"wp-block-image size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"85\" height=\"495\" src=\"https:\/\/yb-isn.fr\/2025\/spc\/wp-content\/uploads\/2026\/03\/image-1.png\" alt=\"\" class=\"wp-image-723\" style=\"width:52px;height:auto\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n<\/div><\/div>\n<\/div><\/div>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n\n\n\n<p class=\"has-black-color has-pale-ocean-gradient-background has-text-color has-background has-link-color wp-elements-eab0fc2726652f918fabf95e6a343cb1 wp-block-paragraph\">4) Sujet de bac<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><a href=\"https:\/\/labolycee.org\/optimisation-de-la-synthese-de-lethanoate-de-benzyle\">https:\/\/labolycee.org\/optimisation-de-la-synthese-de-lethanoate-de-benzyle<\/a><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Lire livre Hatier pages 610 \u00e0 614 1) Regarder la vid\u00e9o : 4 minutes 2) Exercice 3) questionnaire: 12 questions [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_themeisle_gutenberg_block_has_review":false,"footnotes":""},"categories":[8,9],"tags":[],"class_list":["post-698","post","type-post","status-publish","format-standard","hentry","category-devoir-ou-exos-corriges","category-tp"],"_links":{"self":[{"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=\/wp\/v2\/posts\/698","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=698"}],"version-history":[{"count":18,"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=\/wp\/v2\/posts\/698\/revisions"}],"predecessor-version":[{"id":812,"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=\/wp\/v2\/posts\/698\/revisions\/812"}],"wp:attachment":[{"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=698"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=698"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/yb-isn.fr\/2025\/spc\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=698"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}